sql中的left join及on、where前提要害字的区别详解
LEFT JOIN 要害字会从左表 (table_name1) 那里返回所有的行,即便在右表 (table_name2) 中没有匹配的行。
LEFT JOIN 要害字语法
SELECT column_name(s) FROM table_name1 LEFT JOIN table_name2 ON table_name1.column_name=table_name2.column_name
注释:在某些数据库中, LEFT JOIN 称为 LEFT OUTER JOIN。
创建两张表并插入一些数据
create table class( class_id int, class_name varchar(20), class_grade char(1) ); insert into class values (1,'语文','A'); insert into class values (2,'数学','B'); insert into class values (3,'英语','C'); create table score( class_id int, stu_id varchar(20), Score int ); insert into score values (1,'A001',91); insert into score values (2,'A001',95); insert into score values (1,'A002',82); insert into score values (2,'A002',87); insert into score values (3,'B003',65);
查看表中的数据
mysql> select * from class; +----------+------------+-------------+ | class_id | class_name | class_grade | +----------+------------+-------------+ | 1 | 语文 | A | | 2 | 数学 | B | | 3 | 英语 | C | +----------+------------+-------------+ 3 rows in set (0.00 sec) mysql> select * from score; +----------+--------+-------+ | class_id | stu_id | Score | +----------+--------+-------+ | 1 | A001 | 91 | | 2 | A001 | 95 | | 1 | A002 | 82 | | 2 | A002 | 87 | | 3 | B003 | 65 | +----------+--------+-------+ 5 rows in set (0.00 sec) mysql>
比较下面几组查询效果
--要是你对left join足够熟知的话,先不要看效果,是否可以直接说出下面查询的效果
mysql> select * from class A left join score B on A.class_id=B.class_id; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | 1 | A001 | 91 | | 2 | 数学 | B | 2 | A001 | 95 | | 1 | 语文 | A | 1 | A002 | 82 | | 2 | 数学 | B | 2 | A002 | 87 | | 3 | 英语 | C | 3 | B003 | 65 | +----------+------------+-------------+----------+--------+-------+ 5 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and 1=1; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | 1 | A001 | 91 | | 2 | 数学 | B | 2 | A001 | 95 | | 1 | 语文 | A | 1 | A002 | 82 | | 2 | 数学 | B | 2 | A002 | 87 | | 3 | 英语 | C | 3 | B003 | 65 | +----------+------------+-------------+----------+--------+-------+ 5 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and 1=0; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql> select * from class A left join score B on 1=0; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec)
mysql> left join的最重要特色是:无论on背面是什么前提,都会返回左表中的所有行!
mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='语文'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | 1 | A001 | 91 | | 1 | 语文 | A | 1 | A002 | 82 | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 4 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='数学'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 2 | 数学 | B | 2 | A001 | 95 | | 2 | 数学 | B | 2 | A002 | 87 | | 1 | 语文 | A | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 4 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='英语'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 3 | 英语 | C | 3 | B003 | 65 | | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='体育'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql>
要是on背面的前提是左表中的列(and leftTable.colName='***'),左表中知足前提的行和右表中的行进行匹配(依据on leftTable.id=rightTable.id);左表中不知足前提的行,直接输出,其对应的右表中的列都是null。
mysql> select * from class A left join score B on A.class_id=B.class_id and B.Score=90; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and B.Score=65; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 3 | 英语 | C | 3 | B003 | 65 | | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql>
要是on背面的前提是右表中的列(and rightTable.colName='***'),首先会依据(and rightTable.colName='***')过滤掉右表中不知足前提的行;然后,左表中的行依据(on leftTable.id=rightTable.id)和右表中知足前提的行进行匹配。
mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='语文' and B.Score=90; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='语文' and B.Score=91; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | 1 | A001 | 91 | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='体育' and B.Score=90; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id and A.class_name='体育' and B.Score=82; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | NULL | NULL | NULL | | 2 | 数学 | B | NULL | NULL | NULL | | 3 | 英语 | C | NULL | NULL | NULL | +----------+------------+-------------+----------+--------+-------+ 3 rows in set (0.00 sec) mysql>
/**********************过滤前提在on中时**********************/
总结一下,要是 left join on leftTable.id=rightTable.id 后还有其他前提:
(1)and leftTable.colName='***',过滤左表,但是左表不知足前提的行直接输出,并将右表对应局部置为null
(2)and rightTable.colName='***',过滤右表,对左表没有影响
(3)and leftTable.colName='***' and rightTable.colName='***',就是上面(1)和(2)一起发挥作用
无论on背面有哪些前提,left join都要返回左表中的所有行!
mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='语文'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | 1 | A001 | 91 | | 1 | 语文 | A | 1 | A002 | 82 | +----------+------------+-------------+----------+--------+-------+ 2 rows in set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='数学'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 2 | 数学 | B | 2 | A001 | 95 | | 2 | 数学 | B | 2 | A002 | 87 | +----------+------------+-------------+----------+--------+-------+ 2 rows in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='英语'; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 3 | 英语 | C | 3 | B003 | 65 | +----------+------------+-------------+----------+--------+-------+ 1 row in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='体育'; Empty set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where B.Score=90; Empty set (0.01 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where B.Score=91; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | 1 | A001 | 91 | +----------+------------+-------------+----------+--------+-------+ 1 row in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='语文' and B.Score=90; Empty set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='语文' and B.Score=91; +----------+------------+-------------+----------+--------+-------+ | class_id | class_name | class_grade | class_id | stu_id | Score | +----------+------------+-------------+----------+--------+-------+ | 1 | 语文 | A | 1 | A001 | 91 | +----------+------------+-------------+----------+--------+-------+ 1 row in set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='体育' and B.Score=90; Empty set (0.00 sec) mysql> select * from class A left join score B on A.class_id=B.class_id where A.class_name='体育' and B.Score=91; Empty set (0.00 sec) mysql>
/**********************过滤前提在where中时**********************/
过滤前提写在where中时,先依据where前提对表进行过滤,然后再施行left join
总结
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